međutim ovdje imamo return koji se tiče funkcija, i ima posebno značenje
Npr:
I have two copies of the radical, added to another three copies. This gives me a total of five copies:
2,sqrt{3,} + 3,sqrt{3,} = (2 + 3),sqrt{3,}2
3
+3
3
=(2+3)
3
= mathbf{color{purple}{ 5,sqrt{3,} }}=5
3
http://www.purplemath.com/modules/radicals3.htmChoices A, B, and C are incorrect because substituting those values into the equation 3 x plus x, plus x, plus x, minus 3, minus 2, equals 7, plus x, plus x will result in a false statement. For example, in choice B, substituting 1 for x in the equation would give 3 times 1, plus 1, plus 1, plus 1, minus 3, minus 2, equals 7, plus 1, plus 1, which yields the false statement 1 equals 9; therefore, x cannot equal 1.